| Keep a printed
version of this manual in a convenient location and refer
to it often.
Remember:
Always follow appropriate
lab safety procedures when mixing and storing chemicals.
When a substance, called a
solute, is dissolved in another substance, called the solvent, a
solution is formed. A solution is a uniform distribution of solute
in solvent. For example, vinegar is a solution of acetic acid, the
solute, in water, the solvent. The amount of solute in a solvent
is important and can be expressed in several different ways. Some
common units of concentration will be discussed in this manual.
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| 1. |
Molar
solutions |
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Molarity
(M) means the number of moles of solute per liter of solution. To
prepare a 1 M solution, slowly add 1 g formula weight of compound
to 500-mL distilled or deionized water in a 1000-mL volumetric
flask half filled with distilled or deionized water. Allow the
compound to dissolve completely, swirling the flask gently if
necessary. Once the solute is completely dissolved and the
solution is at room temperature, dilute to the mark with water.
Invert the flask several times to mix.
To make a 1 M solution of sodium
hydroxide, slowly add 40 g sodium hydroxide to 500 mL distilled or
deionized water in a 1000-mL volumetric flask. When all the solid
is dissolved and the solution is at room temperature, dilute to
the mark and invert the flask several times to mix.
To make a 1 M solution of acetic acid, dissolve 60.05 g acetic
acid in 500 mL distilled or deionized water in a 1000-mL
volumetric flask. Since acetic acid is a liquid, it may also
be measured by volume. Divide the mass of the acid by its density
(1.049 g/mL) to determine the volume (57.24 mL). Use either 60.05
g or 57.24 mL acetic acid to make the solution. Swirl the flask
gently to mix the solution. When the solution is at room
temperature, dilute to the mark and invert the flask several times
to mix.
|
| 2. |
Percent
solutions |
|
a. |
Mass percent
means the number of grams of solute per 100 g
of solution. For example, 10 g sodium chloride in 90 g water is a
10% by mass solution.
mass
percent = mass of solute/mass of solution
= 10 g / (10 g + 90 g) x 100%
= 10% |
|
b. |
Volume percent
means the number of milliliters of solute per
100 mL of solution. The volume percent of a solution cannot be
calculated directly from the volumes of its components because the
final volume may not equal the sum of the components’ volumes.
To prepare volume percent solutions, first determine the final
volume and concentration of the desired solution and then
determine the amount of solute. Dilute the solute in sufficient
solvent to produce the final volume of desired solution. For
example, to prepare 100 mL of a 10% by volume solution of acetic
acid, dilute 10 mL acetic acid with distilled or deionized water
to make 100 mL of solution.
Note: Solutions
of concentrated reagents, such as 37% hydrochloric acid and 85%
phosphoric acid, are percent solutions by mass. In general,
percent solutions are by mass.
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| 3. |
Dilutions |
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When preparing a dilution, decide
the volume and molar concentration of the resulting solution that
you require. Use the following equation to determine how much of
the concentrated reagent is needed to prepare the diluted
solution,
M reagent
x V reagent = M dilution x V dilution
where M is molarity and V is
volume.
Slowly add the calculated volume
of concentrated reagent to a proper-sized volumetric flask half
filled with distilled or deionized water and swirl the flask to
mix. Once the solution is at room temperature, dilute to the mark
with water and invert the flask several times to mix.
For example, what volume of 10 M
acetic acid is required to prepare 1.0 L of 0.50 M acetic acid?
10 M x V reagent
= 0.50 M x 1.0 L
V reagent = 0.050 L = 50 mL
A volume of 50 mL of 10 M acetic
acid is required to prepare 1.0 L of 0.50 M acetic acid.
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