Comparing the solubility of salt and sucrose

 20 Points

Name:__________________________      Date:____________        Period:______

You can work in groups of up to 4, however each student must turn in a report for credit.

1.    Obtain a cup of NaCl.  Weight the cup and record the mass in the table.

2.    Fill a beaker with 100 mL of water.  Record the volume in the table.

3.    Begin to dissolve the NaCl in the water.  Stop adding NaCl when you can see undissolved crystals at the bottom.

4.    Weigh the cup again.  Record the mass in the table.

5.    Complete the table by computing the mass dissolved and the solubility.

6.    Obtain a cup of sucrose.  Weight the cup and record the mass in the table.

7.    Fill a test tube with 10 mL of water.  Record the volume in the table.  Repeat steps 3 & 4 for the sucrose.

To compute the solubility of NaCl:  C/D        To compute the solubility of sucrose:  C/D*10

The accepted value for NaCl is 37.9g/100g water at 20 degrees C.   Subtract your value from the accepted value.  Divide the result by the accepted value to determine your percentage error. 

The accepted value for sucrose is 203.9g/100g water at 20 degrees C.   Subtract your value from the accepted value.  Divide the result by the accepted value to determine your percentage error. 

Which substance is more soluble?  How can you explain the difference in error percentages?