Determining the concentration (Molarity) of a solution
20 points
Name:__________________________________ Period:______________
There are 3 ways to state the concentration of a solution.
Molarity - The number of moles of a solute dissolved in enough solvent to make 1L of solution. The abbreviation is "M", as in a 1M solution. A 1 molar solution.
Molality - The number of moles of a solute, dissolved in 1L of solution. The abbreviation is "m" as in a 1m solution.
Parts per million - The mass of the component in solution divided by the total mass of the solution multiplied by 106 (one million). The abbreviation is "ppm"
By far the most important is MOLARITY (M). We will concentrate on MOLARITY.
The molarity of a solution is the number of moles of a substance dissolved in enough solvent to make 1L of solution.
The solvent does NOT have to be water!!!!
You determine the molarity of solution as follows:
1. Determine the average atomic mass if the sample is an element, or the gram formula weight if it is a compound.
2. Multiply the mass of the sample by 1/(grams/mole) (grams/mole is from step 1).
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1. What is the molarity of 1L of solution produced by dissolving 8 grams of NaCl in H2O?
8 grams NaCl X 1
Mole NaCl/ 58 grams NaCl = .44 moles NaCl
2. What is the molarity of 100 grams of NaCl dissolved in 1 L of H2O?
100 grams NaCl X 1 Mole NaCl/
58 grams NaCl = 1.72M NaCl
Compute the number of moles of the substance in each of the following samples, and hence the molarity of a 1L solution. Round to 2 places to the right of the decimal. Attach solutions and show all work, as above.
| 24
grams
NaCl |
30
grams
Fe |
200
grams
KBr |
.01
grams
CO2 |
20
grams
KNO3 |
| 6
grams
CH4 |
90
grams
C2H5OH |
60
grams
NH4Cl |
100
grams
H2SO4 |
400
grams
NaC2H3O2 |